14x^2-29x-108=0

Solution for 14x^2-29x-108=0 equation:

14x^2-29x-108=0

a = 14; b = -29; c = -108;
Δ = b2-4ac
Δ = -292-4·14·(-108)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-83}{2*14}=\frac{-54}{28}
=-1+13/14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+83}{2*14}=\frac{112}{28}
=4
$